10b^2-51b+56=0

Solution for 10b^2-51b+56=0 equation:

10b^2-51b+56=0

a = 10; b = -51; c = +56;
Δ = b2-4ac
Δ = -512-4·10·56
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-19}{2*10}=\frac{32}{20}
=1+3/5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+19}{2*10}=\frac{70}{20}
=3+1/2
$